@White Blossom
ok, than I have mentally got it correctly, because I was expecting that integral (classic example to demonstrate the substitution to polar coordinates for solving integral).
@mathprofbrony
You’re right. I graphed it, and squaring the sum of x and y yields a constant-height ridge along the line y=-x. That would be a divergent integral.
@mathprofbrony
Yes, I did in fact make a typo. This was supposed to be the Guassian double integral. This is going to haunt me for the rest of time. Note that I have done little calculus or algebra since high school. How could I have forgotten that x² + y² =/= (x + y)²
In fact the integral diverges, unless Derpy has made a typo.
If the integrand were e{-(x2^ + y2)}, then this would be the standard argument for the Gaussian integral, and it would give that muffin is π.
That the integral as given diverges can actually be shown from the previous statement.
First integrate e^{-(x+y)2} with respect to x over -infinity to infinity. Regardless of the value of y, this is just a translation of the Gaussian, so as a function of y, this is the constant sqrt(π).
But then integrating over y you’re integrating the constant sqrt(π) from -infinity to infinity, and this diverges.
your current filter.True!! Lmao
One could say you got FOIL’d by the numbers.
Yea I know. I only realized it after it was too late lol :)
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(x+y)2=x2+2xy+y2
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Y’all making me miss my college years, when I was constantly in mathemagics classes.
ok, than I have mentally got it correctly, because I was expecting that integral (classic example to demonstrate the substitution to polar coordinates for solving integral).
You’re right. I graphed it, and squaring the sum of x and y yields a constant-height ridge along the line y=-x. That would be a divergent integral.
Yes, I did in fact make a typo. This was supposed to be the Guassian double integral. This is going to haunt me for the rest of time. Note that I have done little calculus or algebra since high school. How could I have forgotten that x² + y² =/= (x + y)²
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Eyyy thanks! (And also thanks for helping out with the tags!)
Any homework under Derpy would be very easy, I bet.
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Don’t even get me started on muffin integrals…